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4m^2-8m-60=0
a = 4; b = -8; c = -60;
Δ = b2-4ac
Δ = -82-4·4·(-60)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*4}=\frac{-24}{8} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*4}=\frac{40}{8} =5 $
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